Electrician (ELE)

2024 Guide - Second Period Package (34 modules) Comments

Date: 9/6/2024 8:53:49 AM
Module: 030201a
Version: 1
Page: 33
Comment: 2024 version of this module: Obj 7, question 3 asks about inductive circuit in an objective about capacitance. The answer on page 41 answers about a capacitive circuit. Question 3 should read: State the phase relationship between Vxc and Ixc in a purely capacitive circuit.
Status: Approved for Review

Date: 9/9/2024 11:32:55 AM
Module: 030201a
Version: 1
Page: 21 and 25
Comment: Page 21, Objective Three Activity, Question 6. - An angle of 198° is used in the question. Page 25, Objective Three Activity Answers, Question 6. - An angle of 196° is used in the answer.
Status: Approved for Review

Date: 9/9/2024 11:38:08 AM
Module: 030201a
Version: 1
Page: 34 and 41
Comment: Page 34, Objective Seven Activity, Question 3. - References an "inductive circuit" in the question. Page 41, Objective Seven Activity Answers, Question 3. - References an "capacitive circuit" in the answer, the answer is correct to a capacitive circuit and the objective is covering capacitive circuits.
Status: Approved for Review

Date: 9/13/2024 3:18:47 PM
Module: 030201a
Version: 1
Page: 25 and 56
Comment: Page 25 - Objective Three Activity - Question 3 Page 56 - Objective Three Activity Answers - Question 3 - Question a) is Answer a) Answer b) is Answer a) Question b) is Answer c) Question c) is Answer d) Question d) has no answer given.
Status: Approved for Review

Date: 9/13/2024 3:47:16 PM
Module: 030201a
Version: 1
Page: 20
Comment: Objective Four - Page 20 - Example Two - Solution Two - 1. "Demand factor, Rule 62-116" should be "Demand factor, Rule 62-118". Rule 62-116 is Ground fault protection After the demand factor of 62-118 is applied the 20 kW hallway electric space heating demand is 17. 5 kW. According to Rule 8-106 3) "whichever is the greater load shall be used in calculating the demand. The 18 kVA air conditioning is the greater load at 100% demand and using the 17.5 kW demand for electric space heating will not accommodate the air conditioning load.
Status: Approved for Review

Date: 9/17/2024 9:32:26 AM
Module: 030201a
Version: 1
Page: 12 and 32
Comment: Objective Three Activity - Page 12 - Question 4. - 106µF capacitor. Objective Three Activity Answers - Page 32 - Question 4. - 500µF capacitor. A 106µF capacitor is correct it should be corrected from 500µF to 106µF in the Objective Three Activity Answers on Page 32 should be corrected to 480 var.
Status: Approved for Review

Date: 9/17/2024 2:36:50 PM
Module: 030201a
Version: 1
Page: 14
Comment: In the right column of the flow chart, second box, the arrow correctly indicates that current increases when inductive reactance decreases but the wording at the bottom of the second box incorrectly states "Current Decreases", it should correctly state Current Increases.
Status: Approved for Review

Date: 9/17/2024 2:43:46 PM
Module: 030201a
Version: 1
Page: 10
Comment: Table 1 - Capacitance effect on voltage The bottom right box in correctly states, "The capacitance tries to prevent the voltage from increasing" It should correctly state, The capacitance tries to prevent the voltage from decreasing
Status: Approved for Review

Date: 9/17/2024 3:25:32 PM
Module: 030201a
Version: 1
Page: 29 and 34
Comment: Page 29 - Self-Test - Question 3., the answer should correctly be a) Quadrature power Page 34 - Self-Test Answers - Question 3., the answer is incorrectly b) Apparent power
Status: Approved for Review

Date: 9/18/2024 2:02:34 PM
Module: 030201a
Version: 1
Page: 53
Comment: Based off the answer key saying the answer is plenum I suspect this question is meant to be ask the blower motor not the combuation air blower: 1. The combustion air blower forces air directly into the a) Heat exchanger. b) Plenum. c) Flue. d) Cold air return duct. The following question: 6. What voltage does an intermittent pilot ignition system require? a) 24 Vac b) 24 Vdc c) 120 Vac d) A very high stepped-up voltage Lists (d) as the answer but the information about intermittent pilot ignition systems early in the module says "Intermittent pilot ignition systems (IP) may utilize either spark ignition or hot surface ignition to light a pilot burner." These two options use different voltages. Question should be more specific about what type of IP is used.
Status: Approved for Review

Date: 3/7/2025 8:26:41 AM
Module: 030201a
Version: 1
Page: 11
Comment: Typo on step 8. Currently reads rule 802. Should read 8-202
Status: Approved for Review

Date: 3/18/2025 9:19:05 AM
Module: 030201a
Version: 1
Page: 32
Comment: Question 4 answer key. The Farads is wrong, making the capacitive reactance also wrong, making the vars also wrong. Side note: can we add brackets in all of the formulas that need them in the modules? Entering the formula without the brackets in the denominator is wrong. If not, can we add a note somewhere when we introduce the XC formula to add the brackets in?
Status: Approved for Review

Date: 3/18/2025 9:14:36 AM
Module: 030201a
Version: 1
Page: 26
Comment: Q=E X I X sin theta =240 V X 6.4 A X 0.6 The 0.6 in the equation is supposed to be a 0.8
Status: Approved for Review

Date: 3/18/2025 9:08:46 AM
Module: 030201a
Version: 1
Page: 48
Comment: The table says 346.3 Amps, it should read 356.3 degrees.
Status: Approved for Review

Date: 6/20/2025 9:29:14 AM
Module: 030201a
Version: 02
Page: 34
Comment: Self-Test Answers 3. b) No. 4 AWG is incorrect, "if all terminations are 75 °C". Self-Test Answers 3. c) No. 6 AWG is correct CE Code 26-208 1) 44 A x 1.35 = 59.4 A Table 2 - 75 °C Column - No.6 AWG - 65 A
Status: Approved for Review

Date: 6/18/2025 3:10:48 PM
Module: 030201a
Version: 02
Page: 8
Comment: The code rule referenced in the fifth paragraph is incorrectly referenced as 62-118, it should correctly reference 62-114.
Status: Approved for Review

Date: 6/18/2025 3:06:38 PM
Module: 030201a
Version: 02
Page: 7 and 17
Comment: Objective Two Activity (Page 7) 1. An apartment building has 24 suites. Each suite has 3000 W of electric space heating and 2500 W of air conditioning. If they cannot be operated at the same time, which of the two would be used towards calculating the main service demand? Objective Two Activity Answers (Page 17) 1. The electric space heating. Rule 8-106 3) indicates to use the larger load. (Incorrect) Correctly, the air conditioning is the larger load. Rule 8-106 3) indicates to use larger load. If one uses the electric space heating, its calculated demand of 56.5 kW as permitted by 62-118 3) does not accommodate for the 60 kW air-conditioning load. Electric space heat = 56.5 kW 24 suites x 3000 W = 72 kW Demand factor, Rule 62-118 10 kW @ 100% = 10 kW 62 kW @75% = 46.5 Air-conditioning = 60 kW 24 suites x 2500 W = 60 kW 60 kW x 100% = 60 kW
Status: Approved for Review

Date: 9/3/2025 9:47:34 AM
Module: 030201a
Version: 2
Page: 17
Comment: Question 3 in Self Test Which conductor is acceptable for a Class 1 signal circuit if EMT is the wiring method and the overcurrent protection is 5A? a) No. 18 AWG copper b) No. 18 AWG aluminum c) No. 16 AWG aluminum d) No. 16 AWG copper Answer given is No. 16 AWG copper. Rule 16-104 Overcurrent protection of Class 1 circuits - subrule 1) b) the protection device shall rated at 5A for No.18 AWG copper (No.16 AWG copper shall be protected by 10A overcurrent device)
Status: Approved for Review

Date: 8/19/2025 2:30:13 PM
Module: 030201a
Version: 02
Page: 46
Comment: Objective Three Activity Answers 3. Table 9G = 27 trade size rigid PVC 7 I assume the last (7) is a typo
Status: Approved for Review

Date: 8/19/2025 2:21:54 PM
Module: 030201a
Version: 02
Page: 19
Comment: I see the term "house" panel has returned in version two when it was properly eliminated in version one. This is a term we have used for years however that does NOT make it proper. This should have correctly been left out as it was in version one and not someone's personal bias be reintroduced because it is something they have used for years or decades.
Status: Approved for Review

Date: 8/19/2025 2:17:46 PM
Module: 030201a
Version: 02
Page: 17, 31, 46, 48 & 49
Comment: FIVE times in this ILM it references TSC, which I assume is trade size conduit however this is NOT common nomenclature and there is no where I can see that provides a clear meaning for the TSC acronym used.
Status: Approved for Review

Date: 11/14/2025 9:33:51 AM
Module: 030201a
Version: 2nd Edition
Page: 29 / 34
Comment: Self Test - Question # 3 - The question on page 29 does not match the answer key on page 34. The question on page 29 asks for the power measured in volt-ampere reactive units. The correct answer is a) Quadrature Power. The incorrect answer key on page 34 states that the correct answer is b) Apparent Power. Please change either the question or that answer key so that they match correctly.
Status: Approved for Review

Date: 11/14/2025 9:01:53 AM
Module: 030201a
Version: 2nd Edition
Page: 12 / 32
Comment: Objective 3 - Question #4 - the values used in the question on page 12 does not match the answer key on page 32. The question on page 12 uses a 106 microfarad capacitor in the calculation. The answer key on page 32 uses a 500 microfarad capacitor in the calculation. Also, the question on page 12 states a current of 4 amperes which is not the current that is drawn from a source of 120 volts and a capacitance of 106 microfarads. The question and answer key need to be re-written with values that are the same and correct.
Status: Approved for Review

Date: 11/12/2025 9:20:27 AM
Module: 030201a
Version: 2
Page: 8-11
Comment: There seems to be some discrepancies regarding rule 62-114 and sizing the breaker to the conductor instead of the load, as well as dividing the conductor by .8 even though a breaker is at 100 percent continuous (and should sized by the load not the conductor to begin with). The handbook has some great examples and a method to follow when sizing conductors and the breakers for electric space heating.
Status: Approved for Review

Date: 10/30/2025 9:57:27 AM
Module: 030201a
Version: 2
Page: 20
Comment: Solution 2- miss quotes 62-118 as 62-116 edit code rule to reflect 2024 CEC changes. It is now 62-118
Status: Approved for Review

Date: 10/29/2025 10:04:39 AM
Module: 030201a
Version: 2
Page: 56
Comment: There are issues with the answers for question 3; answer a) is correct, answer b) repeats answer a) but should be the answer given as answer c). The answer for c) is given in d), and the answer for d) should be cosθ = adj/hyp Θ = cos-1 (3/19) = 80.9 degrees.
Status: Approved for Review

Date: 10/24/2025 8:31:16 AM
Module: 030201a
Version: 2
Page: 32
Comment: As it was mentioned in the Edition 1 of this particular question, the answer key is incorrect. They used 500µF for the answer equation, where the question itself on page 12 states it is a 106µF capacitor, thus making the rest of the answer incorrect. The correct answer is 480 var. Please correct before next edition is published.
Status: Approved for Review

Date: 10/24/2025 8:26:15 AM
Module: 030201a
Version: 2
Page: 56
Comment: For Objective 3 Activity questions, # 3, the answer key on page 56 is incorrect. They give the answer for 3a twice and miss the answer for 3d.
Status: Approved for Review

Date: 9/29/2025 1:16:13 PM
Module: 030201a
Version: 02
Page: 43
Comment: Question 11 does not have the correct answer listed. The calculated load should be 78 325 w.
Status: Approved for Review

Date: 9/7/2025 5:05:23 PM
Module: 030201a
Version: 02
Page: 22
Comment: The answer key for question 6 in objective 2 activity is the wrong rule. It should say 24-108 6) not 24-106 6).
Status: Approved for Review

Date: 8/29/2025 3:17:42 PM
Module: 030201a
Version: 2nd Edition
Page: 1
Comment: Please see internal link to attached chart for addressing cumulative feedback from RDP, atypically submitted via email. Please download and save elsewhere for future maintenance work, as link will likely break in future. https://naitca.sharepoint.com/:b:/r/teams/ILMAdministration/Shared%20Documents/PSL%20working%20area/ILM%20corrections%20from%20Electrical.pdf?csf=1&web=1&e=I5xhpi
Status: Approved for Review

Date: 12/22/2025 11:19:00 AM
Module: 030201a
Version: 2
Page: 21/25
Comment: Q6, the question and the answer key do not match. Question asks for instantaneous voltage at 198° and the key calculates at 196°. simple solution change question to 196°
Status: Approved for Review

Date: 12/22/2025 11:26:56 AM
Module: 030201a
Version: 2
Page: 19
Comment: Table 2 missing decimal in the Voltage, example using 0.707. the voltage should read 169.7V not 1697V
Status: Approved for Review

Date: 12/22/2025 11:36:41 AM
Module: 030201a
Version: 2
Page: 24
Comment: Obj 2 Q5- the explanation of the answer does not account for the 2 mechanical rotations. The answer is 4, but not because of how they explained it. I would include 1440/2 rotations = 720 elec deg per rotation. 720 elec deg/360=2 pairs of poles. Two pairs of poles =4poles
Status: Approved for Review

Date: 12/22/2025 11:38:47 AM
Module: 030201a
Version: 2
Page: 32
Comment: Figure 28, left diagram voltage phasor should have an open arow head
Status: Approved for Review

Date: 12/22/2025 11:40:28 AM
Module: 030201a
Version: 2
Page: 33
Comment: Q3- change "inductive" to "Capacitive"
Status: Approved for Review

Date: 12/22/2025 11:45:15 AM
Module: 030201a
Version: 2
Page: 10
Comment: see bottom chart-When the voltage across capacitor decreases, the capacitance tries to prevent the voltage from DECREASING. (Bottom right quadrant, edit word)
Status: Approved for Review

Date: 12/22/2025 12:05:38 PM
Module: 030201a
Version: 2
Page: 56
Comment: Q3answers correct values to match question 3b 30°, 3c 67.4°, 3d 80.9° Delete the existing 3b answer (it is a duplicate of 3a) The existing 3c) should be 3b The Existing 3d) should be 3c Add new 3d) with (arc cos x(3/19))= 80.9°
Status: Approved for Review

Date: 12/22/2025 1:15:26 PM
Module: 030201a
Version: 2
Page: 16
Comment: above note box- type error- change "vault-amp" to "Volt ampere"
Status: Approved for Review

Date: 12/22/2025 1:25:45 PM
Module: 030201a
Version: 2
Page: 32
Comment: Obj.3, Q4- key doesn't match the question. capacitance should be 106µF and Xc answer is 30.029Ω, then the Vars should be 480var
Status: Approved for Review

Date: 12/22/2025 1:28:23 PM
Module: 030201a
Version: 2
Page: 34
Comment: Q3-correct answer to, a) Quadrature power
Status: Approved for Review

Date: 12/22/2025 1:30:53 PM
Module: 030201a
Version: 2
Page: 14
Comment: right side of chart, middle box, should read "Current Increases". the arrows are correct the word is wrong.
Status: Approved for Review

Date: 12/22/2025 1:33:41 PM
Module: 030201a
Version: 2
Page: 23
Comment: example 3.2- value error on figure 16, change value to Xc2=30Ω to match the solution
Status: Approved for Review

Date: 12/22/2025 1:37:02 PM
Module: 030201a
Version: 2
Page: 42
Comment: last page- the page is not numbered. table 3 the formula for adding capacitors is incorrect- they add inversely in series
Status: Approved for Review

Date: 12/22/2025 1:40:23 PM
Module: 030201a
Version: 2
Page: 38
Comment: Calculate the circuit phase angle - the formula should read cos-1(Rt/Zt) The subscript on the Z is (coil) should be total
Status: Approved for Review

Date: 12/22/2025 1:42:50 PM
Module: 030201a
Version: 2
Page: 35
Comment: Answer for 9b) Phasor diagram is missing the Phasors for Ic1 and Ic2. 1.9A @ 90° and 1.63A @ 90° respectively
Status: Approved for Review

Date: 12/22/2025 1:46:57 PM
Module: 030201a
Version: 2
Page: 10
Comment: first formula for Apparent Power should show power in W not Var second line in proof should read (480W)
Status: Approved for Review

Date: 12/22/2025 1:50:12 PM
Module: 030201a
Version: 2
Page: 18
Comment: Objective 1 question number sequence is missing #3 and cascades misaligned numbering. the answer key page is correct
Status: Approved for Review

Date: 12/22/2025 1:52:44 PM
Module: 030201a
Version: 2
Page: 23
Comment: first paragraph second sentence refers to "Start" winding, it should read "Auxiliary" winding
Status: Approved for Review

Date: 12/22/2025 2:07:07 PM
Module: 030201a
Version: 2
Page: 20
Comment: Solution 2 miss quoted 62-118 as 62-116 Example 4.2 solution 1 halfway down the shown math
Status: Approved for Review

Date: 12/22/2025 2:10:02 PM
Module: 030201a
Version: 2
Page: 30
Comment: step 7. change value in formula from 220V to 240V. The solution is already correct for the 240V value
Status: Approved for Review

Date: 12/22/2025 2:12:27 PM
Module: 030201a
Version: 2
Page: 12
Comment: Q 1, use of "Service box" when "Supply services" matches the content & rule's language
Status: Approved for Review

Date: 12/22/2025 2:14:53 PM
Module: 030201a
Version: 2
Page: 26
Comment: Last line- decimal error it should be 23.2A not 23.8A as proven in the math in the line above
Status: Approved for Review

Date: 12/22/2025 2:21:04 PM
Module: 030201a
Version: 2
Page: 29/34
Comment: Question 3, if the question was Aluminum the key would be correct but it specifies copper. I think it should stay copper and the answer key changed to "c) #No. 6AWG" on pg. 34 Q.3. The answer should be a #6 based off capacitor conductor size and 75 degree TT CU
Status: Approved for Review

Date: 12/22/2025 3:22:41 PM
Module: 030201a
Version: 2
Page: 13
Comment: Q.7 This question is no longer covered in the 2024 CEC or the appendix. or is misaligned with the CEC. 68-058 3)a Unencapsulated, 3b) indicates a grid of #6 copper (300mmx300mm) extending beyond the pool shell by 1.5m. The Ring of copper #6 is mentioned in 3c), specifies for spa or hot tubs, not pools. This question needs a full rewrite or deletion. Suggested rewrite "The reinforcing bars used in the construction of a particular pool are coated with epoxy. A grid of #6awg bare copper from the edge of pool shell extending 1.5 m, at a depth of 110mm below grade. This is an acceptable bonding method according to Rule ___ Subrule____ and appendix ____." This would permit the answer to remain the same as before. or "An inground hot tub installation has a ring of #6 AWG copper 500mm around the perimeter of the pool shell at a depth of 100mm. This is an acceptable bonding method according to Rule ___ Subrule____ and appendix ____." this question would be better answered with subrule 3c) specifically.
Status: Approved for Review

Date: 12/22/2025 3:47:17 PM
Module: 030201a
Version: 2
Page: 3
Comment: the paragraph below Figure 2. references non-conductive coating, this is not stated in 68- 058 2024CEC anymore. Figure 2 describes 68-058 3a) unencapsulated, conductive structural rebar and bonding 4 places. The paragraph misrepresents 68-058 3b) requiring a 300mm square grid of #6 copper extending 1.5m around the pool walls. The loop of #6 is only acceptable for a spa or hot tub (68-058 3c) Suggested edit: If the reinforcing bars are protected with a non-conductive coating, an acceptable equivalent method is to install a grid of #6 copper as per 68-058 3b). Or if it is a spa or hot tub, a loop of #6AWG or larger copper wire installed as per 68-058 3c) is acceptable.
Status: Approved for Review

Date: 12/22/2025 3:49:15 PM
Module: 030201a
Version: 2
Page: 22
Comment: obj 2, answer to Q6. rule reference needs to be 24-108(6). This has not been updated to the 2024 CEC
Status: Approved for Review

Date: 12/22/2025 3:50:46 PM
Module: 030201a
Version: 2
Page: 22
Comment: Obj 2, answer to Q7. rule reference needs to be 24-106(1). This has not been updated to the 2024 CEC
Status: Approved for Review

Date: 12/22/2025 4:18:39 PM
Module: 030201a
Version: 2
Page: 22
Comment: Q8. rule reference needs to be 24-206(2), appendix B This has not been updated to the 2024 CEC
Status: Approved for Review

Date: 12/22/2025 4:22:53 PM
Module: 030201a
Version: 2
Page: 20
Comment: solution - first bullet under 72-102- should read 14-50R for receptacle type not 6-50R
Status: Approved for Review

Date: 12/22/2025 4:24:28 PM
Module: 030201a
Version: 2
Page: 21
Comment: the second reference to rule 72-102 is missing the hyphen (-)
Status: Approved for Review

Date: 12/22/2025 4:26:34 PM
Module: 030201a
Version: 2
Page: 42
Comment: answer to Q2 a) should read "panel" mounted as per figure 14. not locally mounted
Status: Approved for Review

Archived Comments

Year: 2021

1/25/2021 8:18:22 AM
Module: 030205e
Version: 21
Page: 24
Comment: Note Mentioned Rule 4-024 2) b) but there was no such Rule. The rule it was referring to is Rule 4-018 2) b).
Status: Implemented

1/6/2021 9:18:33 AM
Module: 030203g
Version:
Page:
Comment: In some of the modules and evening course packs I find the black and white pictures can be very hard to see things in. Example. I am working on HVAC rooftop units and the one photo of the compressor it is suppose to show a crankcase heater that is band type and I can't see anything or make anything out. I feel even that the modules could be mostly black and white and at least have colour pictures so we can have a better visual on what we are looking at.
Status: Declined

Year: 2019

12/16/2019 2:08:04 PM
Module: 030205d
Version:
Page: 3
Comment: In the middle of page 3 there is a statement indicating "The second subtopic in Section 10 is titled "System and Circuit Grounding". There is no such subsection listed in the index or shown in section 10. This statement should be replaced with a different introduction to the information of this section.
Status: Declined

10/31/2019 1:39:16 PM
Module: 030201b
Version: 21
Page: 16
Comment: In Example 3, it is asking for the instantaneous value of current at 25 degrees. In the equation it uses 'I' instead of 'i' to represent instantaneous current. Page 14 tells us that instantaneous values are represented by lower case letters. The upper case 'I' on page 16 should be a lower case 'i'.
Status: Implemented

1/1/2019 12:00:00 AM
Module: 030204e
Version: 5
Page: 7
Comment: Second paragraph: "Two-wire control uses a maintained contact type of pilot device such as thermostat or float switch." Neither is a maintained type. Please clarify: "can be maintained such as toggle and selector switch or a momentary automatic pilot device such as thermostat or float switch" or something similar. Thanks
Status: Implemented

1/1/2019 12:00:00 AM
Module: 030202e
Version: 5
Page: 14
Comment: Figure 11 shows a motor current of 25.75A but the question (paragraph above) says the current of the motor at 25.60A The calculation/answer is based off the 25.75 in the figure.
Status: Implemented

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