Electrician (ELE)

Date: 12/22/2025 2:10:02 PM
Module: 030201a
Version: 2nd Edition
Page: 30
Comment: Step 7. Change the value in the formula from 220V to 240V. The solution is already correct for the 240V value.
Status: Approved for Review

Date: 12/22/2025 1:52:44 PM
Module: 030201a
Version: 2nd Edition
Page: 23
Comment: First paragraph, second sentence refers to "Start" winding, it should read "Auxiliary" winding.
Status: Approved for Review

Date: 12/22/2025 1:25:45 PM
Module: 030201a
Version: 2nd Edition
Page: 32
Comment: Obj.3, Q4 - key doesn't match the question. Capacitance should be 106µF, and Xc answer is 30.029Ω, then the Vars should be 480var.
Status: Approved for Review

Date: 12/22/2025 11:36:41 AM
Module: 030201a
Version: 2nd Edition
Page: 24
Comment: Obj 2, Q5 - the explanation of the answer does not account for the 2 mechanical rotations. The answer is 4, but not because of how they explained it. I would include 1440/2 rotations = 720 elec deg per rotation. 720 elec deg/360=2 pairs of poles. Two pairs of poles = 4poles.
Status: Approved for Review

Date: 12/22/2025 11:26:56 AM
Module: 030201a
Version: 2nd Edition
Page: 19
Comment: Table 2 missing decimal in the Voltage, example using 0.707. The voltage should read 169.7V, not 1697V.
Status: Approved for Review

Date: 12/22/2025 11:19:00 AM
Module: 030201a
Version: 2nd Edition
Page: 21/25
Comment: Q6, the question and the answer key do not match. The question asks for the instantaneous voltage at 198°, and the key calculates at 196°. Simple solution, change the question to 196°.
Status: Approved for Review

Date: 8/19/2025 2:21:54 PM
Module: 030201a
Version: 2nd Edition
Page: 19
Comment: I see the term "house" panel has returned in version two, when it was properly eliminated in version one. This is a term we have used for years; however, that does not make it proper. This should have been correctly left out, as it was in version one, and someone's personal bias should not be reintroduced because it is something they have used for years or decades.
Status: Approved for Review

Date: 9/17/2024 2:43:46 PM
Module: 030201a
Version: 1st Edition
Page: 10
Comment: Table 1 - Capacitance effect on voltage. The bottom right box incorrectly states, "The capacitance tries to prevent the voltage from increasing." It should correctly state, "The capacitance tries to prevent the voltage from decreasing."
Status: Approved for Review

Date: 9/9/2024 11:32:55 AM
Module: 030201a
Version: 1st Edition
Page: 21 and 25
Comment: Page 21, Objective Three Activity, Question 6. An angle of 198° is used in the question. Page 25, Objective Three Activity Answers, Question 6. An angle of 196° is used in the answer.
Status: Approved for Review

Date: 12/22/2025 11:40:28 AM
Module: 030201c
Version: 2nd Edition
Page: 33
Comment: Q3 - change "inductive" to "capacitive"
Status: Approved for Review

Date: 12/22/2025 11:38:47 AM
Module: 030201c
Version: 2nd Edition
Page: 32
Comment: Figure 28, the left diagram voltage phasor should have an open arrowhead.
Status: Approved for Review

Date: 9/6/2024 8:53:49 AM
Module: 030201c
Version: 1st Edition
Page: 33
Comment: 2024 version of this module: Obj 7, question 3, asks about inductive circuit in an objective about capacitance. The answer on page 41 answers about a capacitive circuit. Question 3 should read: State the phase relationship between Vxc and Ixc in a purely capacitive circuit.
Status: Approved for Review

Date: 9/9/2024 11:38:08 AM
Module: 030201c
Version: 1st Edition
Page: 34 and 41
Comment: Page 34, Objective Seven Activity, Question 3. References an "inductive circuit" in the question. Page 41, Objective Seven Activity Answers, Question 3. References a "capacitive circuit" in the answer. The answer is correct for a capacitive circuit, and the objective is covering capacitive circuits.
Status: Approved for Review

Date: 3/18/2025 9:08:46 AM
Module: 030201d
Version: 1st Edition
Page: 48
Comment: The table says 346.3 Amps. It should read 356.3 degrees.
Status: Approved for Review

Date: 12/22/2025 12:05:38 PM
Module: 030201d
Version: 2nd Edition
Page: 56
Comment: Q3 answers, correct values to match question 3b 30°, 3c 67.4°, 3d 80.9°. Delete the existing 3b answer (it is a duplicate of 3a). The existing 3c) should be 3b. The Existing 3d) should be 3c. Add new 3d) with (arc cos x(3/19))= 80.9°.
Status: Approved for Review

Date: 12/22/2025 11:45:15 AM
Module: 030201d
Version: 2nd Edition
Page: 10
Comment: See the bottom chart - when the voltage across the capacitor decreases, the capacitance tries to prevent the voltage from decreasing. (Bottom right quadrant, edit word).
Status: Approved for Review

Date: 10/29/2025 10:04:39 AM
Module: 030201d
Version: 2nd Edition
Page: 56
Comment: There are issues with the answers to question 3. Answer a) is correct, answer b) repeats answer a), but should be the answer given as answer c). The answer for c) is given in d), and the answer for d) should be cosθ = adj/hyp Θ = cos-1 (3/19) = 80.9 degrees.
Status: Approved for Review

Date: 10/24/2025 8:26:15 AM
Module: 030201d
Version: 2nd Edition
Page: 56
Comment: For Objective 3 Activity questions, #3, the answer key on page 56 is incorrect. They give the answer for 3a twice and miss the answer for 3d.
Status: Approved for Review

Date: 9/13/2024 3:18:47 PM
Module: 030201d
Version: 1st Edition
Page: 25 and 56
Comment: Page 25 - Objective Three Activity - Question 3. Page 56 - Objective Three Activity Answers - Question 3. Question a) is Answer a) Answer b) is Answer a) Question b) is Answer c) Question c) is Answer d) Question d) has no answer given.
Status: Approved for Review

Date: 11/14/2025 9:01:53 AM
Module: 030201e
Version: 2nd Edition
Page: 12 / 32
Comment: Objective 3 - Question #4 - the values used in the question on page 12 do not match the answer key on page 32. The question on page 12 uses a 106 microfarad capacitor in the calculation. The answer key on page 32 uses a 500 microfarad capacitor in the calculation. Also, the question on page 12 states a current of 4 amperes, which is not the current that is drawn from a source of 120 volts and a capacitance of 106 microfarads. The question and answer key need to be re-written with values that are the same and correct.
Status: Approved for Review

Date: 3/27/2025 9:04:17 AM
Module: 030201e
Version:
Page: 12
Comment: Objective 3, Question 4, states that a 106 microfarad Capacitor is connected to a 120v supply @ 50 hz and draws 4 A of current. Calculate reactive power. The answer key states that the Farad value is 0.0005F, which is not 106 Microfarad. 106x10-6 = 0.000106F. Wrong Values given in answer key.
Status: Approved for Review

Date: 3/18/2025 9:19:05 AM
Module: 030201e
Version: 1st Edition
Page: 32
Comment: Question 4 answer key. The Farads is wrong, making the capacitive reactance also wrong, making the vars also wrong. Side note: can we add brackets in all of the formulas that need them in the modules? Entering the formula without the brackets in the denominator is wrong. If not, can we add a note somewhere when we introduce the XC formula to add the brackets in?
Status: Approved for Review

Date: 3/18/2025 9:14:36 AM
Module: 030201e
Version: 1st Edition
Page: 26
Comment: Q=E X I X sin theta=240 V X 6.4 A X 0.6. The 0.6 in the equation is supposed to be a 0.8.
Status: Approved for Review

Date: 12/22/2025 1:30:53 PM
Module: 030201e
Version: 2nd Edition
Page: 14
Comment: Right side of chart, middle box, should read "Current Increases." The arrows are correct, the word is wrong.
Status: Approved for Review

Date: 12/22/2025 1:28:23 PM
Module: 030201e
Version: 2nd Edition
Page: 34
Comment: Q3 - correct answer changed to a) Quadrature power.
Status: Approved for Review

Date: 12/22/2025 1:15:26 PM
Module: 030201e
Version: 2nd Edition
Page: 16
Comment: Above note box - type error - change "vault-amp" to "Volt ampere"
Status: Approved for Review

Date: 11/14/2025 9:33:51 AM
Module: 030201e
Version: 2nd Edition
Page: 29 / 34
Comment: Self Test - Question #3 - The question on page 29 does not match the answer key on page 34. The question on page 29 asks for the power measured in volt-ampere reactive units. The correct answer is a) Quadrature Power. The incorrect answer key on page 34 states that the correct answer is b) Apparent Power. Please change either the question or that answer key so that they match correctly.
Status: Approved for Review

Date: 10/24/2025 8:31:16 AM
Module: 030201e
Version: 2nd Edition
Page: 32
Comment: As mentioned in Edition 1 of this question, the answer key is incorrect. They used 500µF for the answer equation, where the question itself on page 12 states it is a 106µF capacitor, thus making the rest of the answer incorrect. The correct answer is 480 var. Please correct before the next edition is published.
Status: Approved for Review

Date: 9/20/2024 2:07:15 PM
Module: 030201e
Version:
Page:
Comment: Objective 3, question 4, answer page uses 0.0005 F, which is not in the initial question. This causes the answer key in the back of the module to be incorrect.
Status: Approved for Review

Date: 9/17/2024 3:25:32 PM
Module: 030201e
Version: 1st Edition
Page: 29 and 34
Comment: Page 29 - Self-Test - Question 3, the answer should be a) Quadrature power. Page 34 - Self-Test Answers - Question 3, the answer is incorrectly b) Apparent power.
Status: Approved for Review

Date: 9/17/2024 2:36:50 PM
Module: 030201e
Version: 1st Edition
Page: 14
Comment: In the right column of the flow chart, the second box, the arrow correctly indicates that current increases when inductive reactance decreases, but the wording at the bottom of the second box incorrectly states "Current Decreases." It should state "Current Increases."
Status: Approved for Review

Date: 9/17/2024 9:32:26 AM
Module: 030201e
Version: 1st Edition
Page: 12 and 32
Comment: Objective Three Activity - Page 12 - Question 4. - 106µF capacitor. Objective Three Activity Answers - Page 32 - Question 4. - 500µF capacitor. A 106µF capacitor is correct; it should be corrected from 500µF to 106µF in the Objective Three Activity Answers on Page 32, and should be corrected to 480 var.
Status: Approved for Review

Date: 12/22/2025 1:37:02 PM
Module: 030202a
Version: 2nd Edition
Page: 42
Comment: Last page - the page is not numbered. Table 3, the formula for adding capacitors is incorrect - they add inversely in series.
Status: Approved for Review

Date: 12/22/2025 1:33:41 PM
Module: 030202a
Version: 2nd Edition
Page: 23
Comment: Example 3.2 - value error on figure 16, change value to Xc2=30Ω to match the solution.
Status: Approved for Review

Date: 10/4/2024 3:02:53 PM
Module: 030202a
Version: 1st Edition
Page: 22
Comment: Example 3.3. No circuit frequency is given, but the math solution uses 60 hz. Below the diagram on the page.
Status: Approved for Review

Date: 10/4/2024 2:59:47 PM
Module: 030202a
Version: 1st Edition
Page: 21
Comment: Example 3.2. Xc2=20 ohms should read 50 ohms, as per the math below the diagram.
Status: Approved for Review

Date: 12/22/2025 1:40:23 PM
Module: 030202b
Version: 2nd Edition
Page: 38
Comment: Calculate the circuit phase angle - the formula should read cos-1 (Rt/Zt). The subscript on the Z is (coil) should be total.
Status: Approved for Review

Date: 12/22/2025 1:42:50 PM
Module: 030202c
Version: 2nd Edition
Page: 35
Comment: Answer for 9b) Phasor diagram is missing the Phasors for Ic1 and Ic2. 1.9A @ 90° and 1.63A @ 90°, respectively.
Status: Approved for Review

Date: 12/22/2025 1:46:57 PM
Module: 030202d
Version: 2nd Edition
Page: 10
Comment: First formula for Apparent Power should show power in W, not Var. The second line in the proof should read (480W).
Status: Approved for Review

Date: 12/22/2025 1:50:12 PM
Module: 030202e
Version: 2nd Edition
Page: 18
Comment: Objective 1, question number sequence is missing #3, and cascades misaligned numbering. The answer key page is correct.
Status: Approved for Review

Date: 11/27/2024 1:30:54 PM
Module: 030202e
Version: 1st Edition
Page: 22
Comment: Third Paragraph: Original Statement: Because the auxiliary winding is constructed of larger diameter wire and additional turns it provides a substantial magnetic field of its own. New Recommended Statement: When comparing the small wire-size and low number of turns of the split-phase motors start-winding; the two-value capacitor motor's auxiliary-winding is constructed of additional turns of larger sized wire, providing this motor a much stronger overall magnetic effect.
Status: Approved for Review

Date: 9/18/2024 2:02:34 PM
Module: 030203b
Version: 1st Edition
Page: 53
Comment: Based on the answer key saying the answer is plenum, I suspect this question is meant to ask the blower motor, not the combuation air blower: 1. The combustion air blower forces air directly into the a) Heat exchanger. b) Plenum. c) Flue. d) Cold air return duct. The following question: 6. What voltage does an intermittent pilot ignition system require? a) 24 Vac b) 24 Vdc c) 120 Vac d) A very high stepped-up voltage Lists (d) as the answer, but the information about intermittent pilot ignition systems early in the module says "Intermittent pilot ignition systems (IP) may utilize either spark ignition or hot surface ignition to light a pilot burner." These two options use different voltages. The question should be more specific about what type of IP is used.
Status: Approved for Review

Date: 9/3/2025 10:47:46 AM
Module: 030204d
Version: 2nd Edition
Page: 16 and 31
Comment: Two identical schematic diagrams are used in the ILM – figure 6 on page 16, and figure 19 on page 31. This schematic does not function properly. When coil A is energized, coil B will never stay energized, but will chatter since it is controlling itself. When coil A is energized, relay C will never stay energized, but will chatter when the normally open pushbutton controlling it is closed because it is controlling itself. This will also cause the Bell to chatter since it’s controlled by a normally closed C contact. Coil TD is misleading, as it could be considered a timing relay, but there is nothing to denote it as such. The lamp in rung 9 will only energize when the combination pushbutton is pressed and therefore serves no real function except to indicate that the pushbutton has been pressed. The entire schematic needs to be modified to a circuit that functions properly. It is also outrageous that the author is using Figure 6 as the example for a proper schematic diagram. I would recommend that two separate, properly functioning schematics should be used for figure 6 and figure 19 to give the students exposure to different schematic diagrams.
Status: Approved for Review

Date: 6/18/2025 3:10:48 PM
Module: 030205b
Version: 2nd Edition
Page: 8
Comment: The code rule referenced in the fifth paragraph is incorrectly referenced as 62-118. It should correctly reference 62-114.
Status: Approved for Review

Date: 6/18/2025 3:06:38 PM
Module: 030205b
Version: 2nd Edition
Page: 7 and 17
Comment: Page 7 - Objective Two Activity 1. An apartment building has 24 suites. Each suite has 3000 W of electric space heating and 2500 W of air conditioning. If they cannot be operated at the same time, which of the two would be used to calculate the main service demand? Page 17 - Objective Two Activity Answers 1. The electric space heating. Rule 8-106 3) indicates to use the larger load (incorrect). Correctly, the air conditioning is the larger load. Rule 8-106 3) indicates to use the larger load. If one uses the electric space heating, its calculated demand of 56.5 kW as permitted by 62-118 3) does not accommodate the 60 kW air-conditioning load. Electric space heat = 56.5 kW 24 suites x 3000 W = 72 kW Demand factor, Rule 62-118 10 kW @ 100% = 10 kW 62 kW @75% = 46.5 Air-conditioning = 60 kW 24 suites x 2500 W = 60 kW 60 kW x 100% = 60 kW
Status: Approved for Review

Date: 11/12/2025 9:20:27 AM
Module: 030205b
Version: 2nd Edition
Page: 8-11
Comment: There seems to be some discrepancies regarding rule 62-114 and sizing the breaker to the conductor instead of the load, as well as dividing the conductor by .8 even though a breaker is at 100 percent continuous (and should be sized by the load, not the conductor to begin with). The handbook has some great examples and a method to follow when sizing conductors and the breakers for electric space heating.
Status: Approved for Review

Date: 10/30/2025 9:57:27 AM
Module: 030205c
Version: 2nd Edition
Page: 20
Comment: Solution 2 - misquotes 62-118 as 62-116. Edit code rule to reflect 2024 CEC changes. It is now 62-118.
Status: Approved for Review

Date: 8/19/2025 2:30:13 PM
Module: 030205c
Version: 2nd Edition
Page: 46
Comment: Objective Three, Activity Answers 3. Table 9G = 27 trade size rigid PVC 7. I assume the last (7) is a typo.
Status: Approved for Review

Date: 8/19/2025 2:17:46 PM
Module: 030205c
Version: 2nd Edition
Page: 17, 31, 46, 48 & 49
Comment: Five times in this ILM it references TSC, which I assume is trade size conduit; however, this is not common nomenclature, and there is nowhere I can see that provides a clear meaning for the TSC acronym used.
Status: Approved for Review

Date: 3/7/2025 8:26:41 AM
Module: 030205c
Version: 1st Edition
Page: 11
Comment: Typo on step 8. Currently reads rule 802, but should read 8-202.
Status: Approved for Review

Date: 12/22/2025 2:07:07 PM
Module: 030205c
Version: 2nd Edition
Page: 20
Comment: Solution 2 misquoted 62-118 as 62-116. Example 4.2, solution 1, halfway down the shown math.
Status: Approved for Review

Date: 9/29/2025 1:16:13 PM
Module: 030205c
Version: 2nd Edition
Page: 43
Comment: Question 11 does not have the correct answer listed. The calculated load should be 78 325 w.
Status: Approved for Review

Date: 10/4/2024 2:56:51 PM
Module: 030205c
Version: 1st Edition
Page: 20
Comment: Solution 2, math mixed up the AC load and the Heating load in the calculation.
Status: Approved for Review

Date: 9/13/2024 3:47:16 PM
Module: 030205c
Version: 1st Edition
Page: 20
Comment: Objective Four - Page 20 - Example Two - Solution Two - 1. "Demand factor, Rule 62-116" should be "Demand factor, Rule 62-118". Rule 62-116 is ground fault protection. After the demand factor of 62-118 is applied, the 20 kW hallway electric space heating demand is 17. 5 kW. According to Rule 8-106 3) "whichever is the greater load shall be used in calculating the demand." The 18 kVA air conditioning is the greater load at 100% demand, and using the 17.5 kW demand for electric space heating will not accommodate the air conditioning load.
Status: Approved for Review

Date: 3/13/2024 12:55:51 PM
Module: 030205c
Version: Version 25
Page: 17
Comment: Question #1 self test: Either the answer is wrong, or some justification is needed for the number of spaces required in the panel. The text at the bottom outlines the need for (17 total) circuits for the counter plugs (3 ccts) as well as all the other receptacles, lights, and dedicated circuits listed. The appliance schedule lists 3 - 240V appliances, each need 2 spaces (6 total). The fridge and washing machine each require their own ccts based on rule 26-654 a) and b) (2 total). This adds up to 25 circuits so far. A microwave and dishwasher are also listed in the appliance schedule, but for the answer given (28) to be correct, there is only one circuit left for us to use and still have the 2 remaining spaces required by code. The dishwasher should generally get it's own circuit because a) most are direct wired and the breaker is used for the disconnect for that appliance and b) based on it's demand it would not be connected to any of the circuits listed. The microwave could be a countertop model and plug into one of the counter receptacles already listed, but most microwaves have their own enclosure, which would not allow them to be connected to a counter plug, and again, because of its demand, it is not feasible to connect it to a general-use receptacle circuit. If the location of the microwave was given as a counter-top model, the answer given could be correct but this is such a rare occurrence in new construction that it needs to be stated. There is not code that specifically states that the dishwasher and microwave need their own circuits, however when we are given a number of general use receptacle circuits already accounted for we have no idea what the loading of those circuits is, and therefore adding 11.7A or 13.3A to one of those circuits could easily overload them, it also would not be feasible to put them together on a circuit unless you either interlocked them so you couldn't wash dishes and microwave at the same time, or connected them to a 30. Follow-up note: 28 ccts is not enough, you need a minimum of 31, not 29 as my earlier comment suggested. I was thinking it was an apartment, not a house, which made the number of spaces required even higher.
Status: Approved for Review

Date: 12/22/2025 2:12:27 PM
Module: 030205d
Version: 2nd Edition
Page: 12
Comment: Q1, use of "Service box" when "Supply services" matches the content & rules' language.
Status: Approved for Review

Date: 12/22/2025 2:21:04 PM
Module: 030205e
Version: 2nd Edition
Page: 29/34
Comment: Question 3, if the question were aluminum, the key would be correct, but it specifies copper. I think it should stay copper and the answer key changed to "c) #No. 6AWG" on pg. 34 Q.3. The answer should be a #6 based off capacitor conductor size and 75 degree TT CU.
Status: Approved for Review

Date: 12/22/2025 2:14:53 PM
Module: 030205e
Version: 2nd Edition
Page: 26
Comment: Last line - decimal error, it should be 23.2A not 23.8A, as proven in the math in the line above.
Status: Approved for Review

Date: 6/20/2025 9:29:14 AM
Module: 030205e
Version: 2nd Edition
Page: 34
Comment: Self-Test Answers 3 b) No. 4 AWG is incorrect, "if all terminations are 75 °C." Self-Test Answers 3. c) No. 6 AWG is correct. CE Code 26-208 1) 44 A x 1.35 = 59.4 A Table 2 - 75 °C Column - No. 6 AWG - 65 A
Status: Approved for Review

Date: 12/22/2025 4:24:28 PM
Module: 030205f
Version: 2nd Edition
Page: 21
Comment: The second reference to rule 72-102 is missing the hyphen (-)
Status: Approved for Review

Date: 12/22/2025 4:22:53 PM
Module: 030205f
Version: 2nd Edition
Page: 20
Comment: Solution - first bullet under 72-102- should read 14-50R for receptacle type, not 6-50R.
Status: Approved for Review

Date: 12/22/2025 3:47:17 PM
Module: 030205f
Version: 2nd Edition
Page: 3
Comment: The paragraph below Figure 2 references non-conductive coating, which is not stated in 68-058 2024 CEC anymore. Figure 2 describes 68-058, 3a) unencapsulated, conductive structural rebar and bonding 4 places. The paragraph misrepresents 68-058, 3b) requiring a 300mm square grid of #6 copper extending 1.5m around the pool walls. The loop of #6 is only acceptable for a spa or hot tub (68-058 3c). Suggested edit: if the reinforcing bars are protected with a non-conductive coating, an acceptable equivalent method is to install a grid of #6 copper as per 68-058 3b). Or if it is a spa or hot tub, a loop of #6AWG or larger copper wire installed as per 68-058 3c) is acceptable.
Status: Approved for Review

Date: 12/22/2025 3:22:41 PM
Module: 030205f
Version: 2nd Edition
Page: 13
Comment: Q.7. This question is no longer covered in the 2024 CEC or the appendix. Or is misaligned with the CEC. 68-058 3)a Unencapsulated, 3b) indicates a grid of #6 copper (300mmx300mm) extending beyond the pool shell by 1.5m. The Ring of copper #6 is mentioned in 3c), specifies for spa or hot tubs, not pools. This question needs a full rewrite or deletion. Suggested rewrite: "The reinforcing bars used in the construction of a particular pool are coated with epoxy. A grid of #6awg bare copper from the edge of pool shell extending 1.5 m, at a depth of 110mm below grade. This is an acceptable bonding method according to Rule ___ Subrule____ and appendix ____." This would permit the answer to remain the same as before. Or "An inground hot tub installation has a ring of #6 AWG copper 500mm around the perimeter of the pool shell at a depth of 100mm. This is an acceptable bonding method according to Rule ___ Subrule____ and appendix ____." this question would be better answered with subrule 3c) specifically.
Status: Approved for Review

Date: 9/24/2024 11:27:59 AM
Module: 030205f
Version:
Page: 30
Comment: Self Test Question number 3 has the wrong answer labeled in the answer guide. It should be C for No. 6 AWG, but the answer key states it's B No. 4 AWG.
Status: Approved for Review

Date: 9/7/2025 5:05:23 PM
Module: 030205g
Version: 2nd Edition
Page: 22
Comment: The answer key for question 6 in the objective 2 activity is the wrong rule. It should say 24-108 6), not 24-106 6).
Status: Approved for Review

Date: 12/22/2025 4:18:39 PM
Module: 030205g
Version: 2nd Edition
Page: 22
Comment: Q8. Rule reference needs to be 24-206(2), Appendix B. This has not been updated to the 2024 CEC.
Status: Approved for Review

Date: 12/22/2025 3:50:46 PM
Module: 030205g
Version: 2nd Edition
Page: 22
Comment: Obj 2, answer to Q7. Rule reference needs to be 24-206(2). This has not been updated to the 2024 CEC.
Status: Approved for Review

Date: 12/22/2025 3:49:15 PM
Module: 030205g
Version: 2nd Edition
Page: 22
Comment: Obj 2, answer to Q6. Rule reference needs to be 24-108(6). This has not been updated to the 2024 CEC.
Status: Approved for Review

Date: 9/3/2025 9:47:34 AM
Module: 030205h
Version: 2nd Edition
Page: 17
Comment: Question 3 in Self Test: Which conductor is acceptable for a Class 1 signal circuit if EMT is the wiring method and the overcurrent protection is 5A? a) No. 18 AWG copper, b) No. 18 AWG aluminum, c) No. 16 AWG aluminum, d) No. 16 AWG copper. The answer given is No. 16 AWG copper. Rule 16-104 Overcurrent protection of Class 1 circuits - subrule 1) b) the protection device shall be rated at 5A for No. 18 AWG copper (No.16 AWG copper shall be protected by 10A overcurrent device)
Status: Approved for Review

Date: 12/22/2025 4:26:34 PM
Module: 030205j
Version: 2nd Edition
Page: 42
Comment: Answer to Q2 a) should read "panel" mounted as per figure 14. not locally mounted
Status: Approved for Review

Date: 11/1/2024 9:46:10 AM
Module: 030205j
Version: 1st Edition
Page: 37
Comment: In Figure 21, Level Indicator 6 is shown with a panel mount symbol, but the answer key tells students it is a local mount.
Status: Approved for Review